2k^2+4k-28=2

Solution for 2k^2+4k-28=2 equation:

Simplifying
2k2 + 4k + -28 = 2

Reorder the terms:
-28 + 4k + 2k2 = 2

Solving
-28 + 4k + 2k2 = 2

Solving for variable 'k'.

Reorder the terms:
-28 + -2 + 4k + 2k2 = 2 + -2

Combine like terms: -28 + -2 = -30
-30 + 4k + 2k2 = 2 + -2

Combine like terms: 2 + -2 = 0
-30 + 4k + 2k2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-15 + 2k + k2) = 0

Factor a trinomial.
2((-5 + -1k)(3 + -1k)) = 0

Ignore the factor 2.
Subproblem 1
Set the factor '(-5 + -1k)' equal to zero and attempt to solve:

Simplifying
-5 + -1k = 0

Solving
-5 + -1k = 0

Move all terms containing k to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + -1k = 0 + 5

Combine like terms: -5 + 5 = 0
0 + -1k = 0 + 5
-1k = 0 + 5

Combine like terms: 0 + 5 = 5
-1k = 5

Divide each side by '-1'.
k = -5

Simplifying
k = -5
Subproblem 2
Set the factor '(3 + -1k)' equal to zero and attempt to solve:

Simplifying
3 + -1k = 0

Solving
3 + -1k = 0

Move all terms containing k to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1k = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1k = 0 + -3
-1k = 0 + -3

Combine like terms: 0 + -3 = -3
-1k = -3

Divide each side by '-1'.
k = 3

Simplifying
k = 3
Solution
k = {-5, 3}